This will allow you to isolate and solve for the other variable (y/x). This method involves isolating for one variable (x/y) of Line 1 then substituting that variable into Line 2. SUBSTITUTION EQUATION SYSTEMS HOW TOThe best way to show how to solve these kinds of questions are by providing an example to work on. Both methods will bring you to the same solution but with more practice, you will recognize patterns and see which method would work best when given a system. One is substitution and the other is elimination which is meant to be a shortcut. \[\Rightarrow \displaystyle x=2\cdot \left(-\frac\).When dealing with a system of linear equations there are two methods to algebraically solve the question. Now plugging this back into the other equation: Step 4: Plugging back to find the other variable Then, solving for \(y\), by dividing both sides of the equation by \(8\), the following is obtained Putting \(y\) on the left hand side and the constants on the right hand side we get Now, we need to plug the substitution \(\displaystyle x=2y 2\) found from the second equation, into the first equation \(\displaystyle 3x 2y=3\), so we find that: Step 2: Plug the substitution in the other equation Putting \(x\) on the left hand side and \(y\) and the constant on the right hand side we get We use the second equation to solve for \(x\), to find a substitution: \displaystyle 3x 2y
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